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Thursday, January 8, 2015

Compact Convergence of a Power Series (7.46.5)

James Munkres Topology, chapter 7.46, exercise 5:

MathJax TeX Test Page Consider the sequence of functions fn:(1,1) defined by fn(x)=nk=1kxk (a) Show (fn) converges in the topology of compact convergence; conclude that the limit function is continuous.
(b) Show (fn) does not converge uniformly.

Proof: (a) First, note that f(x)=kxk converges for all |x|<1 by the ratio test. Since each compact subset of (1,1) is contained in some interval [x,x](1,1), it will suffice to show fn converges uniformly on [x,x] for all x(0,1). Therefore let |y||x| and observe |f(y)fn(y)|=|k=1kyknk=1kyk|=|k=n+1kyk|k=n+1k|x|k0 as n.

(b) Suppose some n such that |f(x)fn(x)|<1/2 for all x(1,1). Simply choose x(0,1) so that (n+1)xn+11/2, and observe |f(x)fn(x)|=|k=n+1kxk|1/2  

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