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Wednesday, June 12, 2013

Element Collapsing Between Tensor Products (10.4.2)

Dummit and Foote Abstract Algebra, section 10.4, exercise 2:

MathJax TeX Test Page Show 21=0ZZZ/2Z but 2102ZZZ/2Z.

Proof: For the first, notice 21=121=121=12=10=0.

Now, if 21 is zero in the latter tensor product, then by natural extension as a Z-module, for an arbitrary element we have 2ab=(ab)(21)=0 so that 2ZZZ/2Z is zero. However, we have2ZZZ/2ZZ/2ZZ2Z2Z/((2Z)(2Z))2Z/4Z0 

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