Proof: For the first, notice 2⊗1=1⋅2⊗1=1⊗2⋅1=1⊗2=1⊗0=0.
Now, if 2⊗1 is zero in the latter tensor product, then by natural extension as a Z-module, for an arbitrary element we have 2a⊗b=(ab)(2⊗1)=0 so that 2Z⊗ZZ/2Z is zero. However, we have2Z⊗ZZ/2Z≅Z/2Z⊗Z2Z≅2Z/((2Z)(2Z))≅2Z/4Z≇0 ◻
No comments:
Post a Comment