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Friday, April 11, 2014

Problem 7

MathJax TeX Test Page 7. Show that the expressions 2x+3y and 9x+5y are divisible by 17 for the same set of integral values of x and y.

Proof: This is straightforward modular arithmetic. We have 2x+3y0mod 1713(2x+3y)=26x+39y9x+5y0mod 17, since 13 is a unit in /17. Generally, when z | a,b, we have ax+by is divisible by z a prime for the same integral values as cx+dy iff a1bc1dmod z, and when z | a but z | c then (1,0) is a value for ax+by but not for cx+dy, similarly for z | c but z | a, and when z | a,b we have the same values when b and d coincide in divisibility or lack of divisibility by z.

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