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Monday, April 21, 2014

The Fitting Ideal of Level 0 is Independent of Choice of Generators (15.1.36-37)

MathJax TeX Test Page Let M be a finitely generated module over R.

36. (a) Show that for all pn, the Fitting ideal of M is also the ideal in R generated by all the n×n minors of all p×n matrices.
(b) Let A be a fixed p×n matrix as in (a) and let A be a p×n matrix obtained from A by any elementary row or column operation. Show that the ideal in R generated by all the n×n minors of A is the same as the ideal in R generated by all the n×n minors of A.

37. Suppose m1,...,mn and m1,...,mn are two sets of generators for M. Let F be the Fitting ideal calculated with respect to m1,...,mn and let F be the Fitting ideal calculated with respect to m1,...,mn,m1,...,mn.

(a) Show that ms=as,1m1+...+as,nmn for some as,iR for all 1sn, so that (as,1,...,as,n,0,...,0,1,0,...,0) is a relation among m1,...,mn,m1,...,mn.
(b) If A is an n×n matrix whose rows are the coefficients of relations among m1,...,mn, show that det A=det A where A is an (n+n)×(n+n) matrix whose rows are the coefficients of relations among m1,...,mn,m1,...,mn. Deduce FF.
(c) Prove FF and conclude F=F.
(d) Deduce from (c) that the Fitting ideal is independent of choice of generators for M.

Proof: (36)(a) is clear by simply fitting every n×n matrix of relations into a p×n relations matrix whose minor will be included in the latter ideal, and is also clear since every such minor is the determinant of an n×n relations matrix.

(b) Let a be an n×n minor, the determinant of an n×n matrix N. Then let a be the determinant of the matrix N, which is identical to N save for one of its rows or columns being replaced with another part of a row or column in the p×n matrix. Then since determinants are R-bilinear on rows and columns, we have a+r·a is the n×n minor under the column or row operation on p×n by adding r times the specified row or column to another affecting N. Since N is undisturbed, we can retrieve a the original minor in the new ideal, and since this minor was arbitrary, this shows that the two ideals are equal.

(37)(a) Self-explanatory.

(b) Let A be the block matrix [A0BI] where I is the n×n identity, and B is the n×n matrix converting n×1 vectors in terms of mi into n×1 vectors in terms of mi. Then det A=det A where A is a matrix of relations among m1,...,mn,m1,...,mn as desired.

(c) Let A be an (n+n)×(n+n) relations matrix, and observe that its determinant ideal is contained in the (n+n)×(n+n) minor-generated ideal of the (n+2n)×(n+n) block matrix A, where the top (n+n)×(n+n) block is A and the bottom n×(n+n) block is [B  I] as above. By 36(b) we may perform row operations on A to remain A a block matrix [C0BI] where C is an (n+n)×n relations matrix in terms of m1,...,mn. The nontrivial minors of this matrix are those n×n minors of C, which by 36(a) are all contained in F. Since F is the smallest ideal containing all these determinant ideals, we have FF and F=F.

(d) When F is the Fitting ideal calculated with respect to m1,...,mn, we have F=F=F. 

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